Mathematics Tutor: None Selected Time limit: 1 Day

Sep 8th, 2015

Notice first that movies starts at noon.

Movie 1 runs for 70 minutes

or 1 hour and 10 minutes

Movie 2 runs for 105 minutes

or 1 hour and 45 minutes.

Other key information is that there is a 15 minute intermission.

For movie 1 all you have to do is take

noon + 1 hr and 10 minutes +15=the next movie showing.

For movie 2 all you have to do is take

noon + 1 hr and 45 minutes +15= the next movie showing.

You keep doing this until you find a mutual time!

Well,

Movie 1 showings

noon- 1:10pm

1:25pm-2:35pm

2:50pm-4:00pm

4:15pm-5:25pm

5:40pm-6:50pm

7:05pm-8:15pm

8:30pm-9:40pm

10:55pm-11:05 pm

11:20am-12:30am

12:45am-1:55am

2:10am-3:20am

2:35am-3:45am

4am

Movie 2

noon-1:45pm

2:00pm- 3:45pm

4:00pm-5:45pm

6:00pm-7:46pm

8pm-9:45pm

10:00pm-11:45pm

Thus the movie will play again at the same time at 4am on the second day.

Please let me know if you need any clarification. I'm always happy to answer your questions. Leave a positive review if you are happy!
Sep 8th, 2015

I almost ran out of time so I hit submit, but you notice the second movie runs every two hours.

Thus 4am would be included.

Sep 8th, 2015

Sep 8th, 2015

The actual answer is 10pm the next day. The easier trick, so you do not confuse yourself. Is to recognize that every new showing for movie 1 is an hour and 25 minutes long. So, Just going through the list we find in order of new showings

1:25pm

2:50pm

4:15pm

5:40pm

7:05pm

8:30pm

9:55pm

11:20pm

12:45am (day 2 start

2:10am

3:35am

5:00am (not even hour, so we do not stop there)

6:25am

7:50am

9:15am

10:45am

12:00pm

1:30pm

2:55pm

4:20pm

5:45pm

7:10pm

8:35pm

10pm (An even hour! yay!)

Thus it is 10pm on the second day

Sep 8th, 2015

...
Sep 8th, 2015
...
Sep 8th, 2015
Dec 8th, 2016
check_circle