xcos^2(3x) =1 solve for x

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thanks a lot

How to solve for x ? What values of x will satisfy this equation ?

1/2cos(6x)=1/x-1/2

cos(6x) =2/x - 1

cos(6x) = cos^{2}(3x) – sin^{2}(3x) = 1 – 2sin^{2}(3x) = 2cos^{2}(3x) – 1

-[cos^{2}(3x) - sin^{2}(3x)] =2/x - 1

1= 2/x - 1

x=1

Thanks The choice of answers is 1.01 and 1.18 the question is more like <= x <= pie/2 at which values of x do the graphs of f(x)=2 tan(3x) and g(x) = 3x^2 have parallel tangent lines

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