xcos^2(3x) =1 solve for x
Thank you for the opportunity to help you with your question!
thanks a lot
How to solve for x ? What values of x will satisfy this equation ?
cos(6x) =2/x - 1
= cos2(3x) – sin2(3x)
= 1 – 2sin2(3x) = 2cos2(3x)
-[cos2(3x) - sin2(3x)] =2/x - 1
1= 2/x - 1
Thanks The choice of answers is 1.01 and 1.18 the question is more like <= x <= pie/2 at which values of x do the graphs of f(x)=2 tan(3x) and g(x) = 3x^2 have parallel tangent lines
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