Compare the half-life of 235U to 206Lead to the age at 50-50 parent-daughter.

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Compare the half-life of 235U to 206Lead to the age at 50-50 parent-daughter.  What

is the relationship?

Sep 9th, 2015

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t = - (T-half/0.69314) ln(N/No)

 Where t = age 

            N/No = ratio of no. of present parent atoms to original

          T-half = half life of decay

Here when parent-daughter ratio is 50-50

(N/No)= 50/100 =1/2

ln (N/No)= ln (1/2) = -ln 2

                               = - 0.69314

So the relationship becomes

t = - (T-half/0.69314) ln(N/No)

   = - (T-half/0.69314)(- 0.69314)

   =T-half


Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 9th, 2015

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