Thank you for the opportunity to help you with your question!

height of prism formed by wrapper 5 in

windth w and length is w+8

Are can be given by finding the area of each face

379= 2((8 +w) x w ) +(5 x w )+ ( 8+w )x 5))

379/2=w^2 + 8w + 5w +5w +40

379/2= w^2 +13w +40

Solove the RHs by completeing the square

w^2 + 8w +5w +40=379/2

w(w+8) 5(w+8)= 379/2

w+8=379/2 or w+5= 379/2

w=189.5-8 = 181.5 in

or

w=189.5-5

=184.5 in

I ma figuring it out I wil finish it in a shot moment please

Some wrong info somewhere please correct it.

2w^2 + 16w +10w +80=379

2w^2 + 26w=299

we say (b/2 )^2 =a c where a is the first part b is the second part of the equation while c is the last part

2w^2 +26w + 84.5= 299

2w^2 + 13w +13w +84.5 =299

w(w +13) 13(w+13)=299

(W+ 13)^2= 299

w+13= sqrt of 299

w= 17.29162 -13

w=5.29 In

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up