Thank you for the opportunity to help you with your question!
height of prism formed by wrapper 5 in
windth w and length is w+8
Are can be given by finding the area of each face
379= 2((8 +w) x w ) +(5 x w )+ ( 8+w )x 5))
379/2=w^2 + 8w + 5w +5w +40
379/2= w^2 +13w +40
Solove the RHs by completeing the square
w^2 + 8w +5w +40=379/2
w(w+8) 5(w+8)= 379/2
w+8=379/2 or w+5= 379/2
w=189.5-8 = 181.5 in
I ma figuring it out I wil finish it in a shot moment please
Some wrong info somewhere please correct it.
2w^2 + 16w +10w +80=379
2w^2 + 26w=299
we say (b/2 )^2 =a c where a is the first part b is the second part of the equation while c is the last part
2w^2 +26w + 84.5= 299
2w^2 + 13w +13w +84.5 =299
w(w +13) 13(w+13)=299
(W+ 13)^2= 299
w+13= sqrt of 299
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