what is the width of the rectangular prism?

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Sep 10th, 2015

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height of prism formed by wrapper 5 in

windth w and length is w+8

Are can be given by finding the area of each face

379= 2((8 +w) x w  ) +(5 x w )+ ( 8+w )x 5))

379/2=w^2 + 8w + 5w +5w +40

379/2= w^2 +13w +40

Solove the RHs by completeing the square

w^2 + 8w +5w +40=379/2

w(w+8) 5(w+8)= 379/2

w+8=379/2 or w+5= 379/2

w=189.5-8 = 181.5 in

or

w=189.5-5

=184.5 in


I ma figuring it out I wil finish it in a shot moment please

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 10th, 2015

Some wrong info somewhere please correct it.

2w^2 + 16w +10w +80=379

2w^2 + 26w=299

we say (b/2 )^2 =a c where  a is the first part b is the second part of the equation while c is the last part

2w^2 +26w + 84.5= 299

2w^2  + 13w +13w +84.5 =299

w(w +13) 13(w+13)=299

(W+ 13)^2= 299

w+13= sqrt of 299

w= 17.29162 -13

w=5.29 In


Sep 10th, 2015

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