# physic lab report: Measurement of electrical resistance and Ohm’s law

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pallveechem123
School: Carnegie Mellon University

Please find attached the complete workKindly ask in case of any queryPallvee

Measurement of electrical resistance and
Ohm’s law
DATE:……………..

Name:
Section:
Lab partners:

Goals of the experiment:
The goal of this experiment is to study characteristics of resistance, to learn Ohm’s Law in
circuit analysis, and to find out equivalent resistance of series and parallel resistors.

Experiment Procedure:
Ohm’s law:

Connect the ammeter “A”, digital voltammeter “V”, and DC low voltage power supply to the
resistor ' R ' . The power supply and ammeter is in series with the resistor. To measure current
across the resistor, the ammeter is placed in series along the same circuit and to measure volt
drop across the resistor, the voltmeter is placed in parallel. Turn the power supply on with the
voltage control initially set to zero.
Resistors in series and parallel:
Reconfigure the electrical circuit so that all four resistors ( R1 + R2 + R3 + R4 ) in series. Using the
voltage control on the power supply, voltage is set across the combined resistors and current is
measured .The same procedure is repeated with R2 + R3 + R4 . Subsequently, parallel
combinations R1 || R2 , R1 || R3 and R3 || R2 are also undergo the same process.

Data & Analysis:
I ( A)

V R1

0.250
0.50
0.75
1.00

0.1498
0.3052
0.446
0.584

VR5

VR4
1.765
3.69
4.8615
6.487

VR 3

VR 2
0.957
1.907
3.0
4.21

0.2997
0.57
0.812
1.091

1.72
2.55
3.36
3.68

Calculation Table:

Rtheo

R1

R2

R3

l
= 0.528 
A
0.577

l
= 2.123
A
4.34

Rexp

r
%
error Rexp

0.99995
0.998499
0.5771− 0.528
4.34 − 2.123
=
100 =
100
0.528
2.123
= 9.29%
=104

R

l
= 1.056
A

R5

4

1.046

l
= 4.246
A
6.135

l
= 0.860 
A
2.676

0.99995

0.995

0.98336

1.056 −1.046
=
100
1.056
= 0.956%

6.135 − 4.246
=
100
4.246
= 44%%

Data Table:
Combination

I(A )

V (V )

I(A )

V (V )

R1 + R2 + R3 + R4 series

0.50

6.80

01

14.13

R2 + R3 + R4 series

0.50

7.52

01

14.1

R1 R2 parallel

0.50

0.2961

01

0.586

Calculation Table:

2.676 − 0.86
100
0.86
= 2.11%
=

Combination

( Re ) exp ()

( Re ) exp ()

R1 + R2 + R3 + R4
series
R2 + R3 + R4
series
R1 + R2 parallel

13.6

14.13

15...

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Anonymous
awesome work thanks

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