Line EC bisects Line AD at point C. Find value of x if AC=3x +6 and CD= 2x +14

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If line EC bisects the line AD at point C ,

AC=CD; therefore, 3x+6=2x+14

On solving, we have

3x-2x=14-6

x=8

Thus at x=8, AC=24+6=30

and CD=16+14=30

Line EC bisects line AD and point C. Find value of x and AD if AC=5x-8 and CD=16-3x.

AC=CD

5x-8=16-3x

8x=24

x=3

AC=7; CD=7

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