l4-xl = l x/2 7 l I have to solve the absolute value equation

 Algebra Tutor: None Selected Time limit: 1 Day

the lines are absolute value and the x is over the 2

Sep 11th, 2015

There are three cases for this problem

You have to find the domain

|4-x| greater than or equal to zero

x> or equal 4

|x/2+7| great than or equal to zero

x/2>-7

x greater than or equal to 14

Case 1

|4-x|=|x/2+7|

2(4-x=x/2+7)

8-2x=x+14

-x=6

x=-6

Case 2

-|4-x|=|x/2+7|

2(-4+x=x/2+7)

-8+2x=x+14

x=22

This is not the domain

Case 3

-|4-x|=-|x/2+7|

2(-4+x=-x/2-7)

-8+2x=-x-14

3x=-6

x=-2

Therefore our points are -2, and -6.

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Sep 11th, 2015

I'm sorry, I am slightly wrong. I did a check on my answer. Our points are x=-2, and 22

Sep 11th, 2015

Ignore the third case, and my reasoning why 22 is not in there. I logically thought that wrong slightly.

Sep 11th, 2015

I realized I am being really confusing. I am truly sorry. If you give me a moment. I will write it down, and put up a picture.

Sep 11th, 2015
Sep 11th, 2015

Just look at the document, I hope it's less confusing!

Sep 11th, 2015

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Sep 11th, 2015
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Sep 11th, 2015
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