Please help me solve this!!!

Algebra
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A pawnbroker buys a computer and a guitar for $500. He sells the computer at a markup of 40%, but has to take a loss of %10 on the guitar in order to sell it. if he makes a profit of $110 on the sale of the two items, what did he pay for the computer?

Sep 11th, 2015

Thank you for the opportunity to help you with your question!

Let the buying price of computer be X and buying price of guitar be Y.

x+y= 500

x= 500-y

40% x -10%y =110

0.4(500-y ) -0.1y =110

200 -0.4y-0.1y =110

-0.4y-0.1y =110-200

-0.5y =-90

y=-90/-0.5

y= 180

x= 500-180 = 320

the buying price of the computer is thus $320

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 11th, 2015

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