find distance between (4,-6) and (0,3)

Mathematics
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find distance between (4,-6) and (0,3)

Sep 11th, 2015

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  Point a (4,-6) and point b (0,3)


Let x1=4 and Y1 be -6

Let x2 be 0 and y2 be 3

    d= Square root of  ( (X2- X1)^2 + (Y2-Y1)^2)

    Solving in brackets

    (0-4)^2  + (3--6)^2

    =16 + 81

    =97


    Find the square root of the sums

    = Square toot of 97

    = 9.848858 

    Round off to the nearest tenth


    Please let me know if you need any clarification. I'm always happy to answer your questions.
    Sep 11th, 2015

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