Thank you for the opportunity to help you with your question! Hope your day is going well!
Hello, the goal is to solve for y.
1. 2x-4y=1 (let's divide the whole equation by 2)
x-2y=1 (subtract x from both sides)
-2y=-x+1 (divide by -2 to both sides)
Try substituting in different x's to find it's y valus.
x y 1 0 2 1/2 3 1 4 3/2 5 2 6 5/2
So some points are ....(1,0),(2,1/2),(3,1),(4,3/2),(5,2),(6,5/2)....
2. -5+10y=-5 (let's divide the whole equation by 5)
-1+10y=-1 (add one to both sides)
10y=0 (divide by 10 to both sides)
Thus this is a horizontal line (it crosses the y axis, and gives all the points of the x axis).
so some points are ...., (-1,0)(0,0),(1,0),(2,0)....
Please let me know if you need any clarification. I'm always happy to answer your questions. Leave a positive review if you are happy!
I realized I did the wrong things for these problems, because you are supposed to use the substitution method. I will fix it, and give the correct way to do the answer.
Solve for y using the second equation
-5+10y=-5 (add five to both sides)
Substitute y=0 into the first equation
Therefore your answer is x=1, and y=0
Content will be erased after question is completed.