I have never been great at algebra.
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Hello, the goal is to solve for y.
1. 2x-4y=1 (let's divide the whole equation by 2)
x-2y=1 (subtract x from both sides)
-2y=-x+1 (divide by -2 to both sides)
Try substituting in different x's to find it's y valus.
So some points are ....(1,0),(2,1/2),(3,1),(4,3/2),(5,2),(6,5/2)....
2. -5+10y=-5 (let's divide the whole equation by 5)
-1+10y=-1 (add one to both sides)
10y=0 (divide by 10 to both sides)
Thus this is a horizontal line (it crosses the y axis, and gives all the points of the x axis).
so some points are ...., (-1,0)(0,0),(1,0),(2,0)....
I realized I did the wrong things for these problems, because you are supposed to use the substitution method. I will fix it, and give the correct way to do the answer.
Solve for y using the second equation
-5+10y=-5 (add five to both sides)
Substitute y=0 into the first equation
Therefore your answer is x=1, and y=0
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