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Hello, the goal is to solve for y.

1. 2x-4y=1 (let's divide the whole equation by 2)

x-2y=1 (subtract x from both sides)

-2y=-x+1 (divide by -2 to both sides)

y=x/2-1/2

Try substituting in different x's to find it's y valus.

x

y

1

0

2

1/2

3

1

4

3/2

5

2

6

5/2

So some points are ....(1,0),(2,1/2),(3,1),(4,3/2),(5,2),(6,5/2)....

2. -5+10y=-5 (let's divide the whole equation by 5)

-1+10y=-1 (add one to both sides)

10y=0 (divide by 10 to both sides)

y=0

Thus this is a horizontal line (it crosses the y axis, and gives all the points of the x axis).

so some points are ...., (-1,0)(0,0),(1,0),(2,0)....

Please let me know if you need any clarification. I'm always happy to answer your questions. Leave a positive review if you are happy!

Sep 11th, 2015

I realized I did the wrong things for these problems, because you are supposed to use the substitution method. I will fix it, and give the correct way to do the answer.

Solve for y using the second equation

-5+10y=-5 (add five to both sides)

10y=0

y=0

Substitute y=0 into the first equation

2x-4(0)=2

2x-0=2

2x=2

x=1

Therefore your answer is x=1, and y=0

Sep 11th, 2015

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