x+10y=47

5x+4y=5

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Equation 1: x+10y=47

Equation 2: 5x+4y=5

Solve for x in equation 1

x+10y=47 (subtraction 10y from both sides)

x=-10y+47

Substitute x=-10y+47 into the second equation

5(-10y+47)+4y=5

-50y+235+4y=5 (subtract 235 to both sides)

-46y=-230

y=5

Substitute y into equation 1

x+10(5)=47

x+50=47 (subtract 50 to both sides)

x=-3

Therefore your answers are x=-3 and y=5

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