What is the mass in grams of 3.10×1014 iron atoms, each having a mass of 56 amu?

Chemistry
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What is the mass in grams of 3.10×1014 iron atoms, each having a mass of 56 

Sep 11th, 2015

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1 amu=  1.6605  *10^-24 grams

mass of 1 iron atom in grams = 1.6605*56*10^-24

                                                =92.988 *10^-24  grams



Therefore mass of  3.10 *10 ^14  iron atoms = 92.988 *3.10 *10^14 *10^-24

                                                                        =2.88 *10^-8   grams

              

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Sep 11th, 2015

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