s(t)=t squared + 5t + 3; t=1

Calculus
Tutor: None Selected Time limit: 1 Day

Suppose the position of an object moving in a straight line is given by s(t)=t squared+5t+3. Find the instantaneous velocity when t=1.

Sep 11th, 2015

Thank you for the opportunity to help you with your question!

S(t)=t^2 + 5t +3

instantaneous velocity is the derivative of the position  with time,

v(t)=lim of delta t approaching zero((change in S(t)/change in time))=dS(t)/dt

v(t)=dS(t)/dt=2t +5

V(t)=2t +5

 For every t, there is a different velocity at that given instant t, thus called instantaneous velocity .

Thus at instant t=1 second

V(1)=2x1+5=2+5=7 units/second and is directed along a straight line

V(1)=7 units/second i, where i denote the unit vector along the straight line of direction of motion. Remember velocity is a vector and must have not only magnitude but direction as well.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 11th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Sep 11th, 2015
...
Sep 11th, 2015
Dec 8th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer