Applications and equations

Algebra
Tutor: None Selected Time limit: 1 Day

A tugboat goes 160 miles upstream in 10 hours . Return trip downstream takes 5 hours . Find the speed of the tugboat without a current and the speed of the current.

Sep 11th, 2015

Thank you for the opportunity to help you with your question!

Let x = the current speed.

Let b = boat speed.

Remember d=st (distance equals speed times time) 160 = 10(b-x) and 160 = 5 (b+x)

now we can say:

multiply 2nd equation by 2 getting 320=10b +10x

now add the first equation 160 = 10b -10x 320 = 10b +10x --------------- 480 = 20b b=480/20 = 24mph (boat speed) substitute 24 for b in any of the equations above 160= 5(24 + x) 160 = 120 +5x 5x =160 - 120 5x = 40 x =8 mph (current speed)

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 11th, 2015

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Sep 11th, 2015
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