Need help with the problem noted above equation (3,9) that is parallel to 2x+3y=16
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First solve for y
2x+3y=16 (subtract by 2x to both sides)
3y=-2x+16 (divide by )
Thus we know the slope is m=-2/3x
Since parallel lines share the same slope, we know that m=-2/3x for the other line.
Now we can use point slope formula with the point (3,9)
Put in standard form
y-9=-2/3x-2 (add nine to both sides)
Thus the parallel line equation is
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