statistics and probability

label Algebra
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Anne and Bob each have a deck of playing cards. Each flips over a randomly selected card. Assume that all pairs of cards are equally likely to be drawn. Determine the following probabilities: (1) The probability that at least one card is an ace, (2) the probability that the two cards are of the same suit, (3) the probability that neither card is an ace, and (4) the probability that neither card is a diamond or club.

Sep 12th, 2015

1. probabilty that it one draws an ace and the other doesnt

4/52*48/52)*2 = 384/2704 = 24/169

2. 13/52*13/52=1/16

3. 48/52 *48/52 =  144/169

4. 26/52 *26/52 = 1/4

Sep 12th, 2015

no problem and thanks for helping me our, ill add you as my tutor. so regarding question 3, how did you get 48

Sep 12th, 2015

52-4 = 48

probability that it is not an ace = 48/52*48/52

Sep 12th, 2015

thanks mickey gabz for your help, I know you answered my question for free but i wanna send u a dollar for helping me out. How can i do it. I got paypal account

Sep 12th, 2015

Am not sure how you can do it in the site but you can send to my account huntersmike79@gmail.com

Sep 12th, 2015

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Sep 12th, 2015
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Sep 12th, 2015
Oct 24th, 2017
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