What minimum value will be exceeded by 90% of the diameter value?

User Generated

akvat1990

Mathematics

Description

The outside diameters of brushing produced by a certain process are normally distributed wit a mean of 0.498 inches and a standard deviation of 0.002 inches. The specifications require the outside diameter to be 0.500+-0.004 inches for the bushing to be acceptable.

What minimum value will be exceeded by 90% of the diameter value?

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Explanation & Answer

Thank you for the opportunity to help you with your question!

since p (d>dm) = 90% 

z = (dm-dav)/sigma= -1.645

dm = -1.645*0.002+0.498 = 0.4947 


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Anonymous
Excellent resource! Really helped me get the gist of things.

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