Description
The outside diameters of brushing produced by a certain process are normally distributed wit a mean of 0.498 inches and a standard deviation of 0.002 inches. The specifications require the outside diameter to be 0.500+-0.004 inches for the bushing to be acceptable.
What minimum value will be exceeded by 90% of the diameter value?
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Explanation & Answer
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since p (d>dm) = 90%
z = (dm-dav)/sigma= -1.645
dm = -1.645*0.002+0.498 = 0.4947
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