What minimum value will be exceeded by 90% of the diameter value?

Statistics
Tutor: None Selected Time limit: 1 Day

The outside diameters of brushing produced by a certain process are normally distributed wit a mean of 0.498 inches and a standard deviation of 0.002 inches. The specifications require the outside diameter to be 0.500+-0.004 inches for the bushing to be acceptable.

What minimum value will be exceeded by 90% of the diameter value?

Sep 12th, 2015

Thank you for the opportunity to help you with your question!

since p (d>dm) = 90% 

z = (dm-dav)/sigma= -1.645

dm = -1.645*0.002+0.498 = 0.4947 


Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 12th, 2015

Where is the -1.645 from?

Sep 12th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Sep 12th, 2015
...
Sep 12th, 2015
May 30th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer