2x+3y=-3

x+3/4y=-1/2

Solve using the elimination method(ordered pairs... if any)

Thank you for the opportunity to help you with your question!

First, let us number the equations,

2x+3y=-3 (i)

x+3/4y=-1/2 (ii)

Let us multiply (ii) by 2 to get

2x+6/4y=-1 (iii)

Now multiply (iii) by -1 to get

-2x-6/4y=1 (iv)

Now let us add (i) and (iv) as shown below

2x+3y-2x-6/4y=-3+1

simplify to get

3y-6/4y=-2

Simplifying you get

3/2y=-2

y=-2 (2/3)=-4/3

Now use (ii) to find x as below

x+(3/4)(-4/3)=-1/2

x-1=-1/2

x=1/2

Let me if you need any further clarification.

Thanks

What about ordered pairs? Is there any?

(x,y)=(1/2,-4/3) can be an ordered pair, they can be used to locate a point on coordinate plane.

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