Solve the system of equations

Algebra
Tutor: None Selected Time limit: 1 Day

2x+3y=-3

x+3/4y=-1/2

Solve using the elimination method(ordered pairs... if any)

Sep 13th, 2015

Thank you for the opportunity to help you with your question!

First, let us number the equations,

2x+3y=-3              (i)

x+3/4y=-1/2          (ii)

Let us multiply (ii) by 2 to get

2x+6/4y=-1        (iii)

Now multiply (iii) by -1 to get

-2x-6/4y=1         (iv)

Now let us add (i) and (iv) as shown below

2x+3y-2x-6/4y=-3+1

simplify to get

3y-6/4y=-2

Simplifying you get

3/2y=-2

y=-2 (2/3)=-4/3

Now use (ii) to find x as below

x+3/4y=-1/2

x+(3/4)(-4/3)=-1/2

x-1=-1/2

x=1/2

Let me if you need any further clarification.

Thanks



Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 13th, 2015

What about ordered pairs? Is there any?

Sep 13th, 2015

(x,y)=(1/2,-4/3) can be an ordered pair, they can be used to locate a point on coordinate plane.

Sep 13th, 2015

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