4x^2-6x+1=f(x)

Thank you for the opportunity to help you with your question!

Yes i would be very happy to show how to do derivatives

I will do this by example, derivative is normally given by the symbol (d/dx)

if you have a function f(x)=x^n, then its derivative can be expressed as

d/dx(f(x))=d/dx(x^n)=nx^n-1

Therefore d/dx(x^2)=2x^2-1=2x

d/dx(x)=1x^1-1=1x^0=1 (any number raised to zero is 1, so x^0=1)

also derivative of a constant is zero that is d/dx(1)=0 or d/dx(2)=0

Your function is

f(x)=4x^2-6x+1

d/dx(f(x))=4d/dx(x^2)-6d/dx(x)+d/dx(1)

d/dx(f(x))=4(2x)-6(1)+0

=8x-6

Please let me know if you need any clarification.

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