# Assignment on Physics Numerical Problem Homework Help

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### Question Description

I am attaching two files with 21 questions in total. I got some of them worked out, not sure if they are correct, please help me checking them and solve the other ones. Thank you.

### Unformatted Attachment Preview

## Tutor Answer

Hi, I'm sending HW 1 first...

SOLUTION:

m = 3300 lb x (1 kg / 2.20 lb) = 1500 kg

KEf = 0 (since the car is on a stop)

W = Fd = (6000 N)(60 m) = 360000 J

We can compute the deceleration of the object as follows:

F = ma

a = F/m = 6000 N / 1500 kg

a = 4 m/s2

since the car is decelerating, acceleration has a negative sign and is equal to -4 m/s2

We can compute for the initial velocity using the following relationship:

vf2 = v02 + 2ad

0 = v02 + 2(-4 m/s2)(60 m)

v02 = 480 m2/s2

v0 = 21.9 m/s

KE0 = ½ mv02 = ½ (1500 kg)(480 m2/s2)

KE0 = 360000 J

ΔKE = KEf – KE0 = 0 – 360000 J

ΔKE = -360000 J

SOLUTION:

Case 1: M = mv = (1 kg)(2 m/s) = 2 kg∙m/s

Case 2: M = mv = (2 kg)(1 m/s) = 2 kg∙m/s

They have the same momentum

SOLUTION:

Case ...

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