checking my work on parallel and perpendicular lines
Mathematics

Tutor: None Selected  Time limit: 1 Day 
Find an equation for the line passing through the point 2,5 that is parallel to the line x+y=2, then graph both lines. First I put the equation in point slope y=mxtb to get y=1+2. The slope being 1 over 1, And the points being 0,2. Next I used the point intercept form yy1=m(xx1) to get y=1+3. The slope being 1 over 1 and the points being 0,3. Is this correct?
Thank you for the opportunity to help you with your question!
When we find the equation of lines parallel and perpendicular to a given line, we have to remember, the slopes of parallel lines are equal and he slopes of perpendicular lines are "oppositereciprocals."
You started off, right; the equation of the line in slopeintercept is y = 1x + 2; so the slope is 1 (1/1).
For parallel, we do use yy1 = m(xx1) with the point (2,5); giving us...
y  5 = 1 (x  (2))
y  5 = 1 (x + 2)
y  5 = 1x  2
y = 1x + 3; which is what you had (less the "x") Then you could graph this.
For the parallel line, the slope would be the opposite reciprocal of 1; so that would be positive 1.
y  5 = 1(x  (2))
y  5 = x + 2
y = x + 7; This is the equation of the perpendicular line.
I hope this helps. If you have any questions, please let me know.
Please let me know if you need any clarification. I'm always happy to answer your questions.Secure Information
Content will be erased after question is completed.