2 times 2 to the second power over 2 to the eighth power plzzz need help
Thank you for the opportunity to help you with your question!
2 times 2 to the second power over 2 to the eighth power
This can be expressed as:
2 x2^2/2^8 (i)
Remember 2=2^1(two to power one
Also remember: 2^a x 2^b=2^a+b, 1/2^a=2^-a
Therefore: 2 x 2^2 = 2^3
Then (i) becomes
2 x 2^2/2^8=2^3/2^8=2^3 x 2^-8= 2^3-8=2^-5=1/2^5
omggg!! srrry i posted the wrong thing for the question can u switch the ^2 to ^5 plz i got to get this donneeee
Sure, just a moment
Now 2 x 2^5=2^1+5=2^6
2 x 2^5/2^8=2^6/2^8=2^6 x 2^-8=2^6-8=2^-2=1/2^2
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