2 times 2 to the second power over 2 to the eighth power plzzz need help

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2 times 2 to the second power over 2 to the eighth power

This can be expressed as:

2 x2^2/2^8 (i)

Remember 2=2^1(two to power one

Also remember: 2^a x 2^b=2^a+b, 1/2^a=2^-a

Therefore: 2 x 2^2 = 2^3

Then (i) becomes

2 x 2^2/2^8=2^3/2^8=2^3 x 2^-8= 2^3-8=2^-5=1/2^5

omggg!! srrry i posted the wrong thing for the question can u switch the ^2 to ^5 plz i got to get this donneeee

Sure, just a moment

2 x2^5/2^8

Now 2 x 2^5=2^1+5=2^6

Therefore

2 x 2^5/2^8=2^6/2^8=2^6 x 2^-8=2^6-8=2^-2=1/2^2

thhhhx u

thx

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