physics...bottle of champagne

label Physics
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A bottle of champagne is accidentally dropped from a hot air balloon. the balloon is rising at constant velocity of 3 m/s, and the bottle was intitally at rest with respect to the ballon. the bottle takes 8.0 seconds to hit the ground. how high was the ballon when the bottle was dropped, and what is the bottle's velocity just before hitting the ground? 

Sep 14th, 2015

Thank you for the opportunity to help you with your question!

height 

h= 1/2gt^2

h= 1/2 *9.81 m/s^2* 8^2

h= 313.92 m

velocity before hitting the ground

v^2 = 2as

v^2 = 2*9.81* 313.92 = 

v^2 =6159.11

v = square root 6159.11

v= 78.48 m/s

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 14th, 2015

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Sep 14th, 2015
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Sep 14th, 2015
Jun 22nd, 2017
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