# answer these carefully and correctly. or i wont best answer you. thanks :)

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

Oct 3rd, 2015

23.

2ax-5x=2

The goal is to solve for x. Notice both terms on the left hand side have an x. Thus we can factor out an x

x(2a-5)=2 (divide both sides by 2a-5)

x=2/(2a-5).

Thus that is the very last option for 23.

24.

Let's write down what we know

x= the number of people on the school board.

We know that the two sub committees have equal number of members.

Subcommittee 1= (2/3)x-5

subcommittee 2= x/4

Since there are equal number of members, we can simple let subcommittee 1=subcommittee 2

(2/3)x-5=x/4 (multiply the whole equation by 4)

4(2/3)x-20=x (add 20 to both sides and subtract x from both sides).

8/3x-x=20 (multiply by three to get rid of the denominator)

8x-3x=60 (subtract 8x-3x=5x)

5x=60 (divide by 5 from both sides)

x= 12.

therefore there are 12 members on the school board.

Sep 15th, 2015

...
Oct 3rd, 2015
...
Oct 3rd, 2015
Nov 17th, 2017
check_circle