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The goal is to solve for x. Notice both terms on the left hand side have an x. Thus we can factor out an x
x(2a-5)=2 (divide both sides by 2a-5)
Thus that is the very last option for 23.
Let's write down what we know
x= the number of people on the school board.
We know that the two sub committees have equal number of members.
Subcommittee 1= (2/3)x-5
subcommittee 2= x/4
Since there are equal number of members, we can simple let subcommittee 1=subcommittee 2
(2/3)x-5=x/4 (multiply the whole equation by 4)
4(2/3)x-20=x (add 20 to both sides and subtract x from both sides).
8/3x-x=20 (multiply by three to get rid of the denominator)
8x-3x=60 (subtract 8x-3x=5x)
5x=60 (divide by 5 from both sides)
therefore there are 12 members on the school board.
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