Machine Learning and Naive Bayes discussion questions

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Yla_fha

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1. Suppose that we have two bags each containing black and white balls. One bag contains three times as many white balls as blacks. The other bag contains three times as many black balls as white. Suppose we choose one of these bags at random. For this bag we select five balls at random, replacing each ball after it has been selected. The result is that we find 4 white balls and one black. What is the probability what we were using the bag with mainly white balls?


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Question 4 - MLE and Naive Bayes - 10 points These questions are based on maximum likelihood estimator and Naive Bayes 1. Suppose that we have two bags each containing black and white balls. One bag contains three times as many white balls as blacks. The other bag contains three times as many black balls as white. Suppose we choose one of these bags at random. For this bag we select five balls at random, replacing each ball after it has been selected. The result is that we find 4 white balls and one black. What is the probability that we were using the bag with mainly white balls? 2. Given n observations 21, 22, ..., In, Show that the Maximum likelihood estimate of a normal distribution is u == 1;/n and variance is o2 =-1(0; – u)? /n. Hint: consider the formula for normal distribution and find partial derivatives with respect to p and o? 3. Describe how random, max and bayesian classifiers are used for prediction and provide at least one scenario where each classifier can perform as well as the other two. if not possible, state why. vi 4. Suppose that the probability distribution of a random variable that represent categories is given by P(X = k) = 1/2k where k is the category. Only the categories with at least 0.03 are included in the computation of naive bayes estimator. The probability of feature i in category j is given by the formula 1/2 i + j). Compute the probability that a given observation with 3 features is in category 2. 5. Using the same assumptions as the previous part, deduce a general formula for the probability of given n observations is in the category with the index n/2. No need to simplify.
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1

Question 4 - MLE and Naive Bayes - 10 points
1. Solution:
𝑃(π‘Ž1 |𝐡) =

𝑃(𝐡|π‘Ž1 ) βˆ— (𝑃(π‘Ž1 )
𝑃(𝐡|π‘Ž1) βˆ— 𝑃(π‘Ž1 ) + 𝑃(𝐡|π‘Ž1 ) βˆ— 𝑃(π‘Ž2 )

The probability of a b (bags with mostly while balls):
3 4 1 1
5
𝑃(𝐡|π‘Ž1 ) = ( ) ( ) ( )
1 4
4
=

πŸ’πŸŽπŸ“
πŸπŸŽπŸπŸ’

Similarly:
1 4 3 1
5
𝑃(𝐡|π‘Ž2 ) = ( ) ( ) ( )
1 4
4
=

πŸπŸ“
πŸπŸŽπŸπŸ’

Therefore we have:
405
1024
𝑃(π‘Ž1|𝐡) =
405
15
+
1024 1024
=

405
420

= 𝟎. πŸ—πŸ”...


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