5.0 litter rubber balloon is submerged 5.00 meters under the ocean water, where it's new volume is 3.38 liter. Show that the pressure at this depth is 1.48 atmosphere. Use correct number of significant figures.
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P1V1 = P2V2
P1 and V1 are pressure and volume in first case and P2, V2 are pressure and volume in second case
P2 = (P1V1)/V2
P1 = 1.00 atmosphere
V1 = 5.0 liters
V2 = 3.38
=> P2 = (1.0 x 5.0)/3.38 =1.48 atm
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