For the hydrogen atom, the relative energy is -6.053 x 10 to the -20 J for n=6 and -4.447 x 10 to the -20 J for n=7. Calculate the photon energy emitted during the transition E7 to E6.
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energy emmited = -4.447* 10^-20 - -6.053* `10^-20 J
= (-4.447+ 6.053) * 10^ -20 J
= 1.606 * 10^ -20 J
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