The product of two consecutive odd integers is equal to 27 plus six times the sum of the integers. What is the larger integer?
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product of 2 consecutive odd integers
let the numbers be a and b
a x b = 27 + 2(a+b)
Replace a with b+2
b(b+2)= 27 +2((b+2)+b)
b2+2b=27 + 2b +4+2b
Group like terms together
b2 +2b-2b-2b=27 +4
b2 -2b= 31
Because of the timing, let me finish up in five minutes, I will Post the complete answer now
(b−13)(b+3)=0b=13 or -3 Sorry for the delay, I had experienced some network problems.. Thanks
b=13 or -3
Sorry for the delay, I had experienced some network problems.. Thanks
Not satisfied. In my book it says the correct answer is 15 or -1.. Did you mess up somewhere along the way?
Nothing is wrong!
The value is b is 13
the value of a which is equal to b +2 is 15
So your book is right too
The numbers are 13 and 15
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