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The product of two consecutive odd integers is equal to 27 plus six times the sum of the integers. What is the larger integer?

Oct 3rd, 2015

Thank you for the opportunity to help you with your question!

product of 2 consecutive odd integers

let the numbers be a and b

so:

a x b = 27 + 2(a+b)

a=b+2

Replace a with b+2

b(b+2)= 27 +2((b+2)+b)

b2+2b=27 + 2b +4+2b

Group like terms together

b2 +2b-2b-2b=27 +4

b2 -2b= 31

factorize

Because of the timing, let me finish up in five minutes, I will Post the complete answer now

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 18th, 2015

b(b+2)=27+6(b+b+2)

b2+2b=27+6(2b+2)

b2+2b=27+12b+12

b2âˆ’10bâˆ’39=0

factoring gives

(bâˆ’13)(b+3)=0

b=13 or -3

Sorry for the delay, I had experienced some network problems.. Thanks

Sep 18th, 2015

Not satisfied. In my book it says the correct answer is 15 or -1.. Did you mess up somewhere along the way?

Sep 18th, 2015
Let me see!
Sep 18th, 2015

Nothing is wrong!

The value is b is 13

the value of a which is equal to b +2 is 15

So your book is right too

The numbers are 13 and 15

Sep 18th, 2015

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Oct 3rd, 2015
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Oct 3rd, 2015
Sep 26th, 2017
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