##### correction length and width

label Mathematics
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A rectangular lot is yards long and yards wide.

Give the length and width of another rectangular lot that has the same perimeter but a smaller area.

width

length

Oct 3rd, 2015

Say one yard is 6 yards long and 4 yards wide. The perimeter is P = 2L + 2W where L is length and W is width. Therefore the perimeter is 20 yards which is twice the length plus twice the width. The area is A = LW or length times width. Therefore the area is 24 square yards which is the six times four or length times width.

If a second lot is 7 yards long and 3 yards wide then the perimeter is still 20 yards following the formula from above. It is twice the length plus twice the width. The area however is 21square yards since seven times three is 21.

Thus one rectangular lot has a smaller area of 20 square yards and the other has a larger area of 21 square yards but both have the same perimeter of 20 yards.

Sep 18th, 2015

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Oct 3rd, 2015
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Oct 3rd, 2015
Oct 23rd, 2017
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