Algebra 2 Exponents Cant figure out

Algebra
Tutor: None Selected Time limit: 1 Day

(x^2+4)^1/3(3)-(3x)(1/3)(x^2+4)^-2/3(2x)

------------------------------------------------------

[(x^2+4)^1/3]^2

This is a fraction

Oct 3rd, 2015

Thank you for the opportunity to help you with your question!

(x^2+4)^1/3(3)-(3x)(1/3)(x^2+4)^-2/3(2x)

------------------------------------------------------

[(x^2+4)^1/3]^2

1) Let y = x^2+4

2. Simplify the denominator to y^(2/3)

3) Simplify the numerator to y^1 - xy^(-2/3)(2x), then to y^1 - 2(x^2)y^(-2/3)

4) Now we have y^1 - y^(-2/3) * 2(x^2), all divided by y^(2/3)

5) Multiply numerator and denominator by y^(-2/3), getting

6) [y^(1/3) - y^(-4/3) * 2(x^2)] / y^0 

7) which equals (x^2+4)^(1/3) - (x^2+4)^(-4/3) * 2(x^2)

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 19th, 2015

the answer key in my book says 

x^2 + 12

------------

(x^2 +4)^4/3

Sep 19th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Oct 3rd, 2015
...
Oct 3rd, 2015
Mar 26th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer