We're going to set up the system of equations based on each intersection, where traffic out will equal traffic in: x = April, y = Division, z = Broadway, and w = Embankment

At intersection of April and Broadway: Equation 1) 300 = x + z

Intersection of April and Division: Equation 2) x = 100 + y

Broadway and Embankment Equation 3) z + 100 = w

Embankment and Division: Equation 4) w + y = 300

Then start solving the system of equations by substituting in the variables within each equation:

Plug equation 2 into equation 1: 300 = 100 + y + z 200 = y + z

Plug equation 3 into the above equation: 200 = y + w – 100 300 = y + w

This equation is the same as equation 4, which means effectively we have 4 unknowns (w, x, y, z), and 3 equations. So, we will express answers in terms of w (Embankment). Remember that you can plug in the values for 'w' at the end to see if the values you got were correct.

Solve for x, y, and z in terms of w From using equation 1: x = 300 – z And then, substitute equation 3 into above, where (z = w – 100):

x = 300 – (w – 100)

x = 300 – w + 100

x = 400 – w

Using equation 2 to solve for 'y': y = x – 100 y = 400 – w – 100 y = 300 – w

For z value: z = w – 100

w = w

(x, y, z) = (400 – w, 300 – w, w – 100)

Let me know if you have any other concerns! Thanks again!