(x^2+4)^1/3(3)-(3x)(1/3)(x^2+4)^-2/3(2x)

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[(x^2+4)^1/3]^2

This is a fraction

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(x^2+4)^1/3(3)-(3x)(1/3)(x^2+4)^-2/3(2x) = 3(x^2+4)^(1/3) - ((6x²)/(x² + 4)^(2/3))

[(x^2+4)^1/3]^2 = (x^2+4)^2/3

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