1. Rob throws a baseball upwards at 14.2 m/s. His friend, John, is sitting in a tree 4.5m above Rob.

a. Calculate how long it will take to reach John.

b. If John misses the ball as it moves upwards, how long will it take to reach John again.

Thank you for the opportunity to help you with your question!

v^2 = u^2 -2 • a • d

0^2=14.2^2- 2 x a x 4.5

0 = 201.64-9a

9a=201.64

a= 22.4 m/s^2

time taken to reach 4.5m

t= u/a

=14.2/22.4

=0.63 sec

time of flight

T=2t

=2x0.63

=1.268 sec

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