Archimedes drained the water in his tub. 62.562.562, point, 5 liters of water were drained each minute, and the tub was completely drained after 888 minutes.

Graph the amount of water left in the tub (in liters) as a function of time (in minutes).

Thank you for the opportunity to help you with your question!

Let the y be the number of liters in the tub. Let x be the number of minutes passed since draining started. The slope will be -5, as per every minute that passes, the tub will lose 5 liters of water. We also know that the x-intercept (or when the tub is completely empty) is 888 minutes. So the x intercept is (888, 0). Then, we can use the slope interecept form of the the line:

y - y1 = m(x-x1).

Where y1 and x1 represent (x1, y1) a point on the graph (we can use x-intercept here)

M represents the slope (already computed above).

We plug them in:

y - 0 = -5(x - 888)

y = -5x + 4440

Please let me know if you need any clarification. I'm always happy to answer your questions.

Sep 22nd, 2015

To graph it, we see the y-intercept is (0,4440) and the x-intercept is (888,0). Just draw a line connecting these two!