Let f(

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f(x) = -2x^2 + 18x

a. find vertex and determine whether it is a max or minimum

b. find zeros

c. Graph

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f(x)=-2x^{2}+18x

a. At vertex

d(f(x))/dx=

d(-2x^{2}+18x)/dx=0

-4x+18=0

x=9/2

At x=9/2, y=40.5

So vertex is (9/2, 40.5)

At vertex d^{2}(f(x))/dx^{2}=-4 <0

Hence it is maximum

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b. Zeroes are f(x)=0

-2x^{2}+18x=0

x(-2x+18)=0

x=0 or -2x+18=0

Zeroes are x=0,9

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c.

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