Thank you for the opportunity to help you with your question!

The "y" coordinate of f(x) = ax^2 + bx + c, we have to plug the value (-b)/(2a) in for "x" and determine the value of "y."

There is another way to do this, but it involves getting the quadratic into "vertex form." y = (x-h)^2 + k. In this case, "k" is the "y" coordinate of the vertex.

Please let me know if you need any clarification. I'm always happy to answer your questions.