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The "y" coordinate of f(x) = ax^2 + bx + c, we have to plug the value (-b)/(2a) in for "x" and determine the value of "y."
There is another way to do this, but it involves getting the quadratic into "vertex form." y = (x-h)^2 + k. In this case, "k" is the "y" coordinate of the vertex.
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