Find three consecutive integers such that the sum of the first, twice thesecond, and three times the third is − 76.

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let one integer be x

then integers are x,x+1,x+2

sum of the first, twice the second, and three times the third is − 76.

x + 2(x+1)+3(x+2)= -76

x+2x+2+3x+6 = -76

6x+8 = -76

6x = -76 - 8

x = -84/6

x = -14

one integer is -14

other two integers are -14+1 = -13

-14 +2 = -12

answer is

integers are -12 , -13,-14

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