Find three consecutive integers such that the sum of the first, twice thesecond, and three times the third is − 76.
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let one integer be x
then integers are x,x+1,x+2
sum of the first, twice the second, and three times the third is − 76.
x + 2(x+1)+3(x+2)= -76
x+2x+2+3x+6 = -76
6x+8 = -76
6x = -76 - 8
x = -84/6
x = -14
one integer is -14
other two integers are -14+1 = -13
-14 +2 = -12
integers are -12 , -13,-14
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