SOLVING INTEGERS AND SOME MORE


label Algebra
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Find three consecutive integers such that the sum of the first, twice the

second, and three times the third is − 76.

Sep 24th, 2015

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let one integer be x

then integers are x,x+1,x+2

sum of the first, twice the second, and three times the third is − 76.

x + 2(x+1)+3(x+2)= -76

x+2x+2+3x+6 = -76

6x+8 = -76

6x = -76 - 8

 x = -84/6

x = -14


one integer is -14

other two integers are -14+1 = -13

                                    -14 +2 = -12


answer is

integers are -12 , -13,-14


hope you understood..please message if you have any doubts...thank you
Sep 24th, 2015

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