How many grams of fructose would you need to make 4L of a 1.5g/L solution?
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You can begin by determining the number of moles in the concetration of fructose per liter.
1 mole C6H12O6 > 180 grams
how many moles in > 1.5 grams
4 liters would then contain
4 x 0.00833= 0.033 moles
remember 1 mole of fructose = 180 grams
then 0.033 moles would contain........0.033 x 180= 6 Grams
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