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ok I think this is what you want
F(x)= K. a^x and you want to find a and K in a way that if x=0,1,2 then F(x) is 400,120,36
for x=0 you have K(a)^0=400 since K(a)^0 =K then we have K=400
for x=1 you have K(a)^1=120 since K=400 then we have 400.a=120 so a=120/400=0.3
then F(x)= 400.(0.3)^x
for x=2 we just test our F(x) so 400(0.3)^2=400 x 0.3 x 0.3= 36
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