How much heat would be required to melt 3 grams of pure water ice at 0oC and con

Science
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i can't figure this out. Need help before 5 p.m. today

Sep 25th, 2015

Thank you for the opportunity to help you with your question!

specific heat of water   = 4.186 J/g

       weight  =  3 gram 

         temperature =  273 K 

 so heat  =  MST 

                   3 *4.186 * 273  =   3428.334 J/K



Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 25th, 2015

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