How much heat would be required to melt 3 grams of pure water ice at 0oC and con

User Generated

Puryfrn12345678

Science

Description

i can't figure this out. Need help before 5 p.m. today

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Explanation & Answer

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specific heat of water   = 4.186 J/g

       weight  =  3 gram 

         temperature =  273 K 

 so heat  =  MST 

                   3 *4.186 * 273  =   3428.334 J/K



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