mean=35,000 km

standard deviation=1500 km

What percent of tires will have a life that exceeds 26,000 km?

If 2000 tires are purchased, how many tires would you expect to last more than 28,000 km?

Thank you for the opportunity to help you with your question!

1. We need P(x>26000)

first, transform x to z- score: z=(26000-35000)/15000=-.6

P(z>-.6)= 1-P(z<-.6)=1-.2743=.7257=72.57%

2. P(x>28000)=P(z>(28-35)/15)=-.47

P(z>-.47)=1-P(z<-.47)=1-.3192=.6808 or 68.08%

68.08% of 2000=1362 would have life exceeding 28,000 km.

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