Quantum energy and force constant

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

If the quantum of energy for a 1.5-kg mass on a spring is 8.0 * 10^-34 J, what is the force constant of the spring?

Sep 25th, 2015

Thank you for the opportunity to help you with your question!

The energy and the spring constant are related by ; E=1/2KX^2.......(a),  where x,is the spring constant, so plugging in the values; 8.0 *10^-34=1/2*K*X^2 .........(1), since the displacement x is not given. We assume that when a quantum system is in equlibrium the  gravitational force =spring force meaning: mg=kx .........(2), solving for X in equation (2) and plugging in one  (1) and using the givens :

K=(mg)^2/(2*8.0*10^-34),........(3) note the factor 2 is from the equation (a). The answer is ~K=1.35*10^36

Thanks.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 26th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Sep 25th, 2015
...
Sep 25th, 2015
Oct 19th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer