Quantum energy and force constant

Physics
Tutor: None Selected Time limit: 1 Day

If the quantum of energy for a 1.5-kg mass on a spring is 8.0 * 10^-34 J, what is the force constant of the spring?

Sep 25th, 2015

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The energy and the spring constant are related by ; E=1/2KX^2.......(a),  where x,is the spring constant, so plugging in the values; 8.0 *10^-34=1/2*K*X^2 .........(1), since the displacement x is not given. We assume that when a quantum system is in equlibrium the  gravitational force =spring force meaning: mg=kx .........(2), solving for X in equation (2) and plugging in one  (1) and using the givens :

K=(mg)^2/(2*8.0*10^-34),........(3) note the factor 2 is from the equation (a). The answer is ~K=1.35*10^36

Thanks.

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Sep 26th, 2015

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Sep 25th, 2015
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Sep 25th, 2015
Dec 5th, 2016
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