find equation of the line perpendicular and find equation that is parallel to this line and passes through point
Thank you for the opportunity to help you with your question!
Any parallel line must have the same slope, so the equation must be
y = -5/3 x + b, we have to find b
Since (9, -3) lies on this line, substitute x = 9 and y = -3 to get
-3 = -5/3 * 9 + b
-3 = -15 + b
b = 15 -3 =12
Parallel line has equation y = -5/3 x + 12
Perpendicular line must have slope 3/5 since product of slopes of perpendicular lines = -1
Required equation has the form y = 3/5 x + d
again since this line passes through (9, -3)
-3 = 3/5 *9 + d
d= -27/5 -3 = -42/5 (or -8 2/5)
Required equation of perpendicular line is
y = 3/5 x -42/5
Thanks- Hope I can help you again. Can you give me a good review?
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?