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The first step is to identify what the products will be from the reactants. Sodium Hydroxide will break into its two parts, Na+ and OH-. Hydrobromic Acid will also break into its two parts H+ and Br-. (I found the ionic charge, positive or negative, because I know that OH is always negative by itself and H is always positive by itself. Positives and negatives always fuse together, so Na becomes positive in this case and Br is negative.)
Now we have half of the reaction:
Na+OH- + H+Br- --------> ________ + ________
Now to find the products, we take the positive ion from the first reactant, Na+ and the negative ion from the second reactant, Br-, and put them together, making Na+Br-. We also take the negative from the first reactant, OH-, and the positive from the second reactant, H+, and put these together for H2O.
So now we have:
Na+OH- + H+Br- ---------> Na+Br- + H2O.
Now we just have to make sure that the equation is balanced. We do this by counting the number of each element on the left and make sure the same number of that element are on the right side.
There is one Na and one Br on the left, and one Na and one Br on the right. Those elements are balanced.
There is one O and two H's on the left, and one O and two H's on the right. These elements are balanced.
We now know that this is a correctly balanced equation. I hope this helps!Please let me know if you need any clarification. I'm always happy to answer your questions.
Note: Above is the balanced molecular equation. For a "complete ionic equation" we break up each component on both sides of the reaction.
Na+(aq) + OH-(aq) + H+(aq) + Br-(aq) -------> Na+Br- (s) + H20 (l)
Then, for a net ionic reaction, we remove the "spectator ions." These are ions present on both sides of the equation that did not take part in the reaction. In this case, there are no spectator ions because ALL ions reacted to form a new solid or liquid.
Note* "aq" refers to "aqueous" meaning that this substance is an ion. "s" means solid, and (l) means liquid. If a gas had formed, it would be labeled (g) for "gaseous."
The above highlighted equation is therefore both the net ionic and complete ionic equation.
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