I know that the standard for quadratic function is ax2+bx+c but I don't know how to find the vertex or how to find point. A problem you could help with is f(x)=-3x2-6x
Thank you for the opportunity to help you with your question!
So you want to find the vertex of f(x)=-3x^2-6x :
to find the vertex should derivate the function :
f'(x) = -6x - 6
so should we determinate the f '(x) = 0 so is : x = -1
so we have : f'(x) > 0 at ]-infinity , -1] and f'(x) < 0 at [ -1 , + infinity[
and : f(-1) = 9
the vertex is the point A(-1,9)
if you don't understand something just ask please
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