I know that the standard for quadratic function is ax2+bx+c but I don't know how to find the vertex or how to find point. A problem you could help with is f(x)=-3x2-6x

Thank you for the opportunity to help you with your question!

So you want to find the vertex of f(x)=-3x^2-6x :

to find the vertex should derivate the function :

f'(x) = -6x - 6

so should we determinate the f '(x) = 0 so is : x = -1

so we have : f'(x) > 0 at ]-infinity , -1] and f'(x) < 0 at [ -1 , + infinity[

and : f(-1) = 9

so :

the vertex is the point A(-1,9)

if you don't understand something just ask please

i glad to work with you each time you have any other question or assignment just invite me i will give you the detailed answer ok

Good luck

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up