AP physics. one answer to this

Physics
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A particle moving at a velocity of 2.3 m in the positive x direction is given an acceleration of 4.9 m/s^2 in the positive y direction for 4.3s.  What is the speed of the particle? Answer in units of m/s. 

Sep 27th, 2015

Thank you for the opportunity to help you with your question!

  velocity in Y direction   = 4.9 * 4.3 = 21.07 m/S

velocity in y direction  =  2.3 m/s

        final velocity  =   square root ( 2.3^2 + 21.07^2)   = 21.19 m/s 



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Sep 27th, 2015

sorry ................................

Thank you for the opportunity to help you with your question!

  velocity in Y direction   = 4.9 * 4.3 = 21.07 m/S

velocity in x  direction  =  2.3 m/s

        final velocity  =   square root ( 2.3^2 + 21.07^2)   = 21.19 m/s 


Sep 27th, 2015

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Sep 27th, 2015
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Sep 27th, 2015
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