AP physics. one answer to this

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A particle moving at a velocity of 2.3 m in the positive x direction is given an acceleration of 4.9 m/s^2 in the positive y direction for 4.3s.  What is the speed of the particle? Answer in units of m/s. 

Sep 27th, 2015

Thank you for the opportunity to help you with your question!

  velocity in Y direction   = 4.9 * 4.3 = 21.07 m/S

velocity in y direction  =  2.3 m/s

        final velocity  =   square root ( 2.3^2 + 21.07^2)   = 21.19 m/s 



..........................................................................

 

                          


                   

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 27th, 2015

sorry ................................

Thank you for the opportunity to help you with your question!

  velocity in Y direction   = 4.9 * 4.3 = 21.07 m/S

velocity in x  direction  =  2.3 m/s

        final velocity  =   square root ( 2.3^2 + 21.07^2)   = 21.19 m/s 


Sep 27th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Sep 27th, 2015
...
Sep 27th, 2015
Jun 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer