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Mathematics

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A furniture shop refinishes tables. Employees use one of two methods to refinish each table.
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The question is not clear but after copy and paste you get the values:
A furniture shop refinishes tables. Employees use one of two methods to refinish each table.
Method I takes
1.5 hours and the material costs
$9. Method II takes
2.5 hours, and the material costs
$4. Next week, they plan to spend
181 hours in labor and
$580 in material for refinishing tables. How many tables should they plan to refinish with each method?
Solution
Let x be the number of tables finished with method 1 and y be the number of tables finished with method 2.
Hours?
1.5x +2.5y=181
x= (1812.5y)/1.5
Cost?
9x +4y = 580
9((1812.5y)/1.5)) +4y =580
To simplify divide the 9 with 1.5. You get 6. Therefore it becomes
6(1812.5y) +4y =580
1086  15y + 4y =580
1086580=15y4y
11y=506
y=46
Use the value to find the value of x
1.5x +2.5(46)=181
1.5x +115 =181
1.5x = 66
x=66/1.5
x=44
So they should make 44 tables using method 1 and 46 tables using method 2.
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