##### Need help figuring this out!

 Physics Tutor: None Selected Time limit: 1 Day

Sep 27th, 2015

Thank you for the opportunity to help you with your question!

55 mph ≈ 80.7 ft/s

trucks:

Ek = ½mv² = ½ * (8730lb / 32.2 ft/s²) * (80.7ft/s)² = 882 100 ft·lb

worst case friction: Ffw = µmg = 0.55 * 8730lb = 4802 lb

→ stopping distance d = Ek / Ffw = 184 ft

best case friction: Ffb = 0.941 * 8730lb = 8215 lb

→ stopping distance d = Ek / Ffb = 107 ft

bugs:

Ek = ½ * (1190lb / 32.2ft/s²) * (80.7ft/s)² = 120 240 ft·lb

worst case friction: Ffw = 0.55 * 1190lb = 655 lb

→ stopping distance d = 184 ft

best case friction: Ffb = 0.941 * 1190lb = 1120 lb

→ stopping distance d = 107 ft

Given that the maximum allowable distance is 155 ft, we've got to reduce the maximum allowable Ek of the vehicles, and it appears not to matter which one we analyze.

worst case friction for bug over 155 ft entails Work = 655lb * 155ft = 101 525 ft·lb

This corresponds to Ek = 101 525 ft·lb = ½ * (1190lb / 32.2ft/s²) * v²

→ v ≈ 74 ft/s ≈ 50 mph ← maximum desired speed limit

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 28th, 2015

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Sep 27th, 2015
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Sep 27th, 2015
Dec 2nd, 2016
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