(3x^2+2)(-4x-5)

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=3x^2*-4x +3x^2*-5+2 * -4x + 2* -5

= - 12x^3 - 15x^2 - 8x -10....................................answer

Could you explain that one?

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open the brackets and multiply each term with other

now multiply the numbers in each term and add the exponents of variables

= -12 x^(2+1) - 15 x^2 - 8x -10

= - 12x^3 - 15x^2 - 8x -10

please message the step in which you have doubt if any

There is one the -12x^2+1.. is that part of the exponent?

3x^2*-4x

= -12x^(2+1) you can see that there are x^2 and x so when we multiply that it becomes x^(2+1) = x^3

and the others are numbers 3 and -4 ,so 3*-4 = -12,

so together it is -12x^3

= -12x^3

you got it?

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