Multiply the polynomial

Algebra
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(3x^2+2)(-4x-5)

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Sep 28th, 2015

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(3x^2+2)(-4x-5)

=3x^2*-4x +3x^2*-5+2 * -4x + 2* -5

=  - 12x^3 - 15x^2 - 8x -10....................................answer


hope you understood..please message if you have any doubts...thank you
Sep 28th, 2015

Could you explain that one?

Sep 28th, 2015

sure...please wait

Sep 28th, 2015

(3x^2+2)(-4x-5)

open the brackets and multiply each term with other

=3x^2*-4x +3x^2*-5+2 * -4x + 2* -5

now multiply the numbers in each term and add the exponents of variables

=  -12 x^(2+1) - 15 x^2 - 8x -10

=  - 12x^3 - 15x^2 - 8x -10



please message the step in which you have doubt if any

Sep 28th, 2015

There is one the -12x^2+1.. is that part of the exponent?

Sep 28th, 2015

3x^2*-4x

=  -12x^(2+1)    you can see that there are x^2 and x so when we multiply that it becomes x^(2+1) = x^3

                                     and the others are numbers 3 and -4 ,so 3*-4 = -12,

                                  so together it is  -12x^3


-12x^3

Sep 28th, 2015

you got it?

Sep 28th, 2015

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