finding the distance a jet travels

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a 747  jet, traveling at a velocity of 70. meters per second north, touches down on a runway. the jet slows to a rest at the rate of 2.0 meters per second^2. calculate the total distance traveled on the runway as it is brought to rest.

Sep 28th, 2015

Thank you for the opportunity to help you with your question!

Applying Newton's laws of motion

V^2 = U^2+2aS, where V = 0, final velocity, U = 70 m/s, initial velocity and acceleration, a = -2 m/s^2, decelerating, S is distance

0 = U^2 - 2as;  2aS = U^2

S = sqrt (U^2/2a) = sqrt ( 70^2/2*2) = 1225 m

Distance = 1225 m

Regards Friend


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Sep 28th, 2015

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